Skip to main content

Python Unittest

Unittest library helps you to test your program and inform you whether it is working fine. It is useful to recheck if a program is running fine when you make certain changes to any related code. Making a test file makes testing easy. All you need to do later is run this file and it will inform you if a program that you are testing is working fine with all possible inputs.

Here is an example of Unitest file working on another file:

CAP.PY FILE

def capitalizing_text(text):
    '''
    Input string's first letter is capitalized.
    '''
    return text.cap()

TEST_CAP.PY FILE

#importing unitest library
import unittest
import cap

class TestCap(unittest.TestCase):

#functions in test file must start with the word 'test'
    def test_one_word(self):
        text = 'python'
#running the program
        result = cap.capitalizing_text(text)
#The following line checks if the result and expected result match
        self.assertEqual(result, 'Python')

#second function to test a different set of input
    def test_multiple_words(self):
        text='monty python'
        result = cap.capitalizing_text(text)
        self.assertEqual(result, 'Monty Python')

#The following if statement is used to run the program directly from command prompt without having to call from a different file
if __name__=='__main__':
    unittest.main()

On running the test file, it will inform you that there is an error with the result in the second function. It is not returning as expected. On making the following changes to the program and running the test program again, the errors will be gone.

CAP.PY

def capitalizing_text(text):
    '''
    Input string's first letter is capitalized.
    '''
    return text.title()

Comments

Popular posts from this blog

Python - List - Append, Count, Extend, Index, Insert, Pop, Remove, Reverse, Sort

🐍 Advance List List is widely used and it's functionalities are heavily useful. Append Adds one element at the end of the list. Syntax list1.append(value) Input l1 = [1, 2, 3] l1.append(4) l1 Output [1, 2, 3, 4] append can be used to add any datatype in a list. It can even add list inside list. Caution: Append does not return anything. It just appends the list. Count .count(value) counts the number of occurrences of an element in the list. Syntax list1.count(value) Input l1 = [1, 2, 3, 4, 3] l1.count(3) Output 2 It returns 0 if the value is not found in the list. Extend .count(value) counts the number of occurrences of an element in the list. Syntax list1.extend(list) Input l1 = [1, 2, 3] l1.extend([4, 5]) Output [1, 2, 3, 4, 5] If we use append, entire list will be added to the first list like one element. Extend, i nstead of considering a list as one element, it joins the two lists one after other. Append works in the following way. Input l1 = [1, 2, 3] l1.append([4, 5]) Output...

Difference between .exec() and .execPopulate() in Mongoose?

Here I answer what is the difference between .exec() and .execPopulate() in Mongoose? .exec() is used with a query while .execPopulate() is used with a document Syntax for .exec() is as follows: Model.query() . populate ( 'field' ) . exec () // returns promise . then ( function ( document ) { console . log ( document ); }); Syntax for .execPopulate() is as follows: fetchedDocument . populate ( 'field' ) . execPopulate () // returns promise . then ( function ( document ) { console . log ( document ); }); When working with individual document use .execPopulate(), for model query use .exec(). Both returns a promise. One can do without .exec() or .execPopulate() but then has to pass a callback in populate.

683 K Empty Slots

  Approach #1: Insert Into Sorted Structure [Accepted] Intuition Let's add flowers in the order they bloom. When each flower blooms, we check it's neighbors to see if they can satisfy the condition with the current flower. Algorithm We'll maintain  active , a sorted data structure containing every flower that has currently bloomed. When we add a flower to  active , we should check it's lower and higher neighbors. If some neighbor satisfies the condition, we know the condition occurred first on this day. Complexity Analysis Time Complexity (Java):  O(N \log N) O ( N lo g N ) , where  N N  is the length of  flowers . Every insertion and search is  O(\log N) O ( lo g N ) . Time Complexity (Python):  O(N^2) O ( N 2 ) . As above, except  list.insert  is  O(N) O ( N ) . Space Complexity:  O(N) O ( N ) , the size of  active . Approach #2: Min Queue [Accepted] Intuition For each contiguous block ("window") of  k  po...