Python - Find e to the Nth Digit

🐍 Enter a number and have the program generate e up to that many decimal places. Keep a limit to how far the program will go.

from math import e

def epric(n):
return '%.*f' % (n, e)

if __name__ == '__main__':

correct_input = False
while not correct_input:
print('Precision must be between 1 and 51')
precision = int(input('Number of decimal places: '))
if 51 >= precision > 0:
correct_input = True
print(epric(precision))

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Vinit Khandelwal

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