Python - Find common elements in two lists, avoid None values

Finding common values between two lists is easy in Python when compared to Javascript. First remove all None values. Because the in-built function will consider None also as a value to compare. If we don't want that then remove it using filter function. Then make one of the lists as set and use intersection function as follows:

Run the code here: https://repl.it/@VinitKhandelwal/CommonElementsList

list1 = ['a','b','c',None]

list2 = ['c','d','e',None]

list3 = list(filter(lambda x: x is not None, list1))

list4 = list(filter(lambda x: x is not None, list2))

print(list3)

print(list4)

print(list(set(list3).intersection(list4)))

list1 = [1,2,3,4,None,5,6]

list2 = [3, 5, 7, 9, None]

list3=[]

for i in list1:

  for j in list2:

    if i is not None and i == j:

      list3.append(i)

      break

print(f"{list3} - function to find common values")

OUTPUT

[3, 5] - function to find common values ['a', 'b', 'c'] ['c', 'd', 'e'] ['c']

Comments

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