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Javascript - From an array, return 2 numbers that add up to a given target

Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

Solution - Brute Force

var twoSum = function(nums, target) {
    for(var i = 0; i < nums.length; i++) {
        for(var j = i + 1; j < nums.length; j++) {
            if(nums[j] == target - nums[i]) {
                return [i, j]
            }
        }
    }
    throw new Error(`No two numbers such that they total-up to ${target}`);
};

console.log(twoSum([2,7,11,15], 9));

Finished
Runtime: 84 ms

Your input
[2,7,11,15]
9
stdout
[ 0, 1 ]
Output
[0,1]
Expected
[0,1]

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