Skip to main content

Where to use Number() and parseInt() in Javascript?

Where to use Number() and parseInt() in Javascript?
Number(object) tries to convert the entire string to a number(which can also be a float) while parseInt(object) parses up to first non-digit and returns whatever value has been parsed.
So, if you have "1234@gmail.com" and you want to get 1234 out of it, then use parseInt("1234@gmail.com");
But, if you have "1234" and you want to convert the entire string as one number then use Number("1234");

Comments

Post a Comment

Popular posts from this blog

Difference between .exec() and .execPopulate() in Mongoose?

Here I answer what is the difference between .exec() and .execPopulate() in Mongoose? .exec() is used with a query while .execPopulate() is used with a document Syntax for .exec() is as follows: Model.query() . populate ( 'field' ) . exec () // returns promise . then ( function ( document ) { console . log ( document ); }); Syntax for .execPopulate() is as follows: fetchedDocument . populate ( 'field' ) . execPopulate () // returns promise . then ( function ( document ) { console . log ( document ); }); When working with individual document use .execPopulate(), for model query use .exec(). Both returns a promise. One can do without .exec() or .execPopulate() but then has to pass a callback in populate.
1 comment
Read more

Python - List - Append, Count, Extend, Index, Insert, Pop, Remove, Reverse, Sort

🐍 Advance List List is widely used and it's functionalities are heavily useful. Append Adds one element at the end of the list. Syntax list1.append(value) Input l1 = [1, 2, 3] l1.append(4) l1 Output [1, 2, 3, 4] append can be used to add any datatype in a list. It can even add list inside list. Caution: Append does not return anything. It just appends the list. Count .count(value) counts the number of occurrences of an element in the list. Syntax list1.count(value) Input l1 = [1, 2, 3, 4, 3] l1.count(3) Output 2 It returns 0 if the value is not found in the list. Extend .count(value) counts the number of occurrences of an element in the list. Syntax list1.extend(list) Input l1 = [1, 2, 3] l1.extend([4, 5]) Output [1, 2, 3, 4, 5] If we use append, entire list will be added to the first list like one element. Extend, i nstead of considering a list as one element, it joins the two lists one after other. Append works in the following way. Input l1 = [1, 2, 3] l1.append([4, 5]) Output...
Post a Comment
Read more

269. Alien Dictionary

  Solution This article assumes you already have some confidence with  graph algorithms , such as  breadth-first search  and  depth-first searching . If you're familiar with those, but not with  topological sort  (the topic tag for this problem), don't panic, as you should still be able to make sense of it. It is one of the many more advanced algorithms that keen programmers tend to "invent" themselves before realizing it's already a widely known and used algorithm. There are a couple of approaches to topological sort;  Kahn's Algorithm  and DFS. A few things to keep in mind: The letters  within a word  don't tell us anything about the relative order. For example, the presence of the word  kitten  in the list does  not  tell us that the letter  k  is before the letter  i . The input can contain words followed by their prefix, for example,  abcd  and then  ab . These cases will never ...
Post a Comment
Read more